Question

Factorise the given equation 2y3 + y2 - 2y - 1​

Answer 1

Answer:

-1 is answer and make me as brain list please

Answer 2

Given that 2y³ + y² – 2y – 1

Now Factorizing

2y³ + y² – 2y – 1

= y² (2y + 1) -1 (2y + 1)

= (2y + 1)(y² – 1)

= (2y + 1)(y² – 1²)

By algebraic identity:

a² – b² = (a + b) (a – b)

(y² – 1²) = (y + 1)(y – 1)

(y² – 1²) can be written as  (y + 1) (y – 1)

∴ (2y + 1)(y² – 1²)= (2y + 1) (y + 1) (y – 1)

Therefore,

2y³ + y² – 2y – 1 = (2y + 1) (y + 1) (y-1)