Question

Factorise the given expression :
21x^2-8x-4​

Answer 1

Answer:

HI BUDDY

$21 {x}^{2} - 8x - 4 = 0 \\ 21 {x}^{2} - 14x + 6x - 4 = 0 \\ 7x(3x - 2) + 2(3x - 2) = 0 \\ (7x + 2)(3x - 2) = 0 \\ x = \frac{ - 2}{7 } \: andx = \frac{2}{3} \\ \\ hope \: this \: helps$

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Answer 2

Answer:

21x^2-8x-4

by middle term splitting method:

=21x^2-14x+6x-4(because the product of 14 and 6 is 84 and by subtracting them we get 8)

=7x(3x-2)+2(3x-2)

=(3x-2)(7x+2)

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