Question

factorise the given polynomial (x^2-x)^2 - 8 (x^2-x) + 12​

Answer 1

Namaste mate! Here is your answer.

$( {x}^{2} - x)^{2} - 8( {x}^{2} - x) + 12 \\ let \: x \: be \: ( {x}^{2} - x) \: be \: a\\ = {a}^{2} - 8a + 12 \\ = {a}^{2} - (6 + 2)a + 12 \\ = {a}^{2} - 6a - 2a + 12 \\ = a(a - 6) - 2(a - 6) \\ = (a - 6)(a - 2) \\ \\ putting \: the \: value \: of \\ a \: \: \: i.e. \: ( {x}^{2} - x) \\ = ( {x}^{2} - x - 6)( {x}^{2} - 2)$