Factorise the given polynomial
(y²+5y)(y²+5y-2)
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Step-by-step explanation:
y
2
+5y)(y
2
+5y−2)−24=0
Let, y
2
+5y=a
a(a−2)−24=0
a
2
−2a−24=0
a
2
−6a+4a−24=0
a(a−6)+4(a−6)=0
(a−6)(a+4)=0
a−6=0 or a+4=0
By resubstituting,
y
2
+5y=a
y
2
+5y−6=0 or y
2
+5y+4=0
y
2
+6y−y−6=0 or y
2
+4y+y+4=0
y(y+6)−1(y+6)=0 or y(y+4)+1(y+4)=0
(y+6)(y−1)=0 or (y+4)(y+1)=0
y−1=0 or y+6=0 or y+4=0 or y+1=0
∴y=1 or y=−6 or y=−4 or y=−1
y=−6,−4,−1,1.
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