Question

Factorise the given question

1-(6-c)^2​

Answer 1

$\texttt{\;\;\;\;1 - (6-c)²}$

$\texttt{= (1)² - (6-c)²}$

$\texttt{= [1+(6-c)] [1-(6-c)]}$

$\texttt{= (1+6-c) (1-6+c)}$

$\texttt{= (7-c) (c-5)}$

$\texttt{Here, the formula a²-b² = (a+b)(a-b) is used}$