Question

factorise the given trinomial a^2/4b^2-2/3+4b^2/9a^2​

Answer 1

Step-by-step explanation:

$\frac{ {a}^{2} }{ {4b}^{2} } - \frac{2}{3} + \frac{ {4b}^{2} }{ {9a}^{2} } \\ \\ = ({ \frac{a}{2b} })^{2} - 2 \times \frac{a}{2b} \times \frac{2b}{3a} + ({ \frac{2b}{3a} })^{2} \\ \\ = ( { \frac{a}{2b} - \frac{2b}{3a} })^{2} \: \: \: \: \: \: \: \: ( {a}^{2} - 2ab + {b}^{2} = {(a + b)}^{2} ) \\ = ( \frac{a}{2b} - \frac{2b}{3a} )( \frac{a}{2b} - \frac{2b}{3a} ) \\ ({a}^{2} = a \times a)$

//Hope this will Helped You//

//Please mark it as Brainliest//