factorise the grouping
9x+13+27ax+39a
Answers
Answered by
17
Given -
9x + 13 + 27ax + 39a
Rearranging
= 9x + 27ax + 13 + 39a
= 9x ( 1 + 3a ) + 13 ( 1 + 3a )
= ( 9x + 13 ) ( 1 + 3a )
^^"
9x + 13 + 27ax + 39a
Rearranging
= 9x + 27ax + 13 + 39a
= 9x ( 1 + 3a ) + 13 ( 1 + 3a )
= ( 9x + 13 ) ( 1 + 3a )
^^"
Answered by
0
Answer:
(9x+3) (13a+1)
Step-by-step explanation:
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