Question

Factorise The Identity x¹²+y¹²

Answer 1

Answer:

(x^4 + y^4) [x^8 -x^4y^4 + y^8]

Step-by-step explanation:

(x^4)^3 + (y^4)^3

a^3 + b^3 = (a+b)(a^2-ab+b^2)

a = x^4, b = y^4

(x^4+y^4)[(x^4)^2 - (x^4)(y^4) + (y^4)^2

(x^4 + y^4)[x^8 - (xy)^4 + y^8]