Question

factorise the method of grouping term n² +6n +an+ 6a in long​

Answer 1

Answer:

Factoring n2-6n-6

The first term is, n2 its coefficient is 1 .

The middle term is, -6n its coefficient is -6 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -6 .

-6 + 1 = -5

-3 + 2 = -1

-2 + 3 = 1

-1 + 6 = 5

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored