Math, asked by riswanasherin, 5 days ago

factorise the polinomial x^6-1 in to linear factors​

Answers

Answered by akshayabongoni
0

Step-by-step explanation:

Use difference of squares, difference of cubes and sum of cubes:

[1]:

a

2

b

2

=

(

a

b

)

(

a

+

b

)

[2]:

a

3

b

3

=

(

a

b

)

(

a

2

+

a

b

+

b

2

)

[3]:

a

3

+

b

3

=

(

a

+

b

)

(

a

2

a

b

+

b

2

)

x

6

1

=

(

x

3

)

2

1

2

=

(

x

3

1

)

(

x

3

+

1

)

by [1]

=

(

x

3

1

3

)

(

x

3

+

1

3

)

=

(

x

1

)

(

x

2

+

x

+

1

)

(

x

+

1

)

(

x

2

x

+

1

)

by [2] and [3]

Answered by has42000
0

Answer:

x^{6} - 1 = (x-1) (x+1) ( x^{2} \\ + x +1) ( x^{2} \\ - x +1)

Step-by-step explanation:

Attachments:
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