Factorise the polynomial () = 20
2 − 9 + 1 and find the zeros
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Explanation:
Given polynomial, f(x) = 20x² - 9x + 1
⇒ f(x) = 20x² - (5 + 4)x + 1
⇒ f(x) = 20x² - 5x - 4x + 1
⇒ f(x) = 5x (4x - 1) - 1 (4x - 1)
⇒ f(x) = (4x - 1) (5x - 1)
This is the required factorization.
In order to find the zeros, we take f(x) = 0
⇒ (4x - 1) (5x - 1) = 0
∴ either 4x - 1 = 0 or 5x - 1 = 0
⇒ either 4x = 1 or 5x = 1
⇒ either x = 1/4 or x = 1/5
∴ the zeros of f(x) are 1/4 and 1/5
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