Factorise the polynomial 6ab - bsquare - - 2bc - 12ac
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Answered by
8
Hey mate!!
6ab - b² - 2bc - 12 ac
6ab - 12ac - b² - 2bc
6a(b - 2c) - b( b - 2c)
=> (b - 2c)(6a - b)
Thanks for the question!!
6ab - b² - 2bc - 12 ac
6ab - 12ac - b² - 2bc
6a(b - 2c) - b( b - 2c)
=> (b - 2c)(6a - b)
Thanks for the question!!
Answered by
9
Heya!
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♦Factorize ♦
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✴Given Expression =>
==================
==> 6ab - b² - 2bc - 12ac
==> 6ab - 12ac - b² - 2bc
==> 6a ( b - 2c ) - b ( b - 2c )
==> ( 6 a - b ) ( b - 2c )
======================================================
--------
=======================================================
♦Factorize ♦
===========
✴Given Expression =>
==================
==> 6ab - b² - 2bc - 12ac
==> 6ab - 12ac - b² - 2bc
==> 6a ( b - 2c ) - b ( b - 2c )
==> ( 6 a - b ) ( b - 2c )
======================================================
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