Question

factorise the polynomial 6x cube +19x sq+ 19x+6

Answer 1

Answer:

(x+1)(x+2/3)(x+3/2)

Step-by-step explanation:

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Answer 2

Answer:-

This is the required solution.Check it out.

$\sf 6 {x}^{3} + 19 {x}^{2} + 19x + 6$

$\sf = 6 {x}^{3} + 6 + 19 {x}^{2} + 19x$

$\sf = 6 ({x}^{3} + 1) + 19x(x +1)$

$\sf = 6 (x+ 1)( {x}^{2} - x + 1) + 19x(x +1)$

$\sf = (x+ 1)(6 {x}^{2} - 6x + 6 + 19x)$

$\sf = (x+ 1)(6 {x}^{2} + 13x + 6)$

$\sf = (x+ 1)(6 {x}^{2} + 9x + 4x+ 6)$

$\sf = (x+ 1)(3x(2x + 3) + 2(2x+ 3))$

$\sf = (x+ 1)(3x + 2)(2x+ 3)$

This is the required answer.