Question

factorise the polynomial 6x cube +19x sq+ 19x+6 pls give it asap

Answer 1

Answer:-

This is the required solution.Check it out.

$\sf 6 {x}^{3} + 19 {x}^{2} + 19x + 6$

$\sf = 6 {x}^{3} + 6 + 19 {x}^{2} + 19x$

$\sf = 6 ({x}^{3} + 1) + 19x(x +1)$

$\sf = 6 (x+ 1)( {x}^{2} - x + 1) + 19x(x +1)$

$\sf = (x+ 1)(6 {x}^{2} - 6x + 6 + 19x)$

$\sf = (x+ 1)(6 {x}^{2} + 13x + 6)$

$\sf = (x+ 1)(6 {x}^{2} + 9x + 4x+ 6)$

$\sf = (x+ 1)(3x(2x + 3) + 2(2x+ 3))$

$\sf = (x+ 1)(3x + 2)(2x+ 3)$

This is the required answer.

Answer 2

Answer:

This is the required solution.Check it out.

\sf 6 {x}^{3} + 19 {x}^{2} + 19x + 66x

3

+19x

2

+19x+6

\sf = 6 {x}^{3} + 6 + 19 {x}^{2} + 19x=6x

3

+6+19x

2

+19x

\sf = 6 ({x}^{3} + 1) + 19x(x +1)=6(x

3

+1)+19x(x+1)

\sf = 6 (x+ 1)( {x}^{2} - x + 1) + 19x(x +1)=6(x+1)(x

2

−x+1)+19x(x+1)

\sf = (x+ 1)(6 {x}^{2} - 6x + 6 + 19x)=(x+1)(6x

2

−6x+6+19x)

\sf = (x+ 1)(6 {x}^{2} + 13x + 6)=(x+1)(6x

2

+13x+6)

\sf = (x+ 1)(6 {x}^{2} + 9x + 4x+ 6)=(x+1)(6x

2

+9x+4x+6)

\sf = (x+ 1)(3x(2x + 3) + 2(2x+ 3))=(x+1)(3x(2x+3)+2(2x+3))

\sf = (x+ 1)(3x + 2)(2x+ 3)=(x+1)(3x+2)(2x+3)

This is the required answer.

hoe it helps u in ur question