Question

Factorise the polynomial 8x³-(2x-y)³

Answer 1

(a^3 - b^3) = (a - b_(a^2 + ab + b^2)

where a = (2x)^3
and b = (2x - y)^3

[8x^3 - (2x - y)^3 = (2x - (2x - y))(4x^2 + 2x(2x - y) + (2x - y)^2 =

y(8x^2 - 2xy + (4x^2 - 4xy + y^2)) = y(12x^2 - 6xy + y^2)]

Answer 2

Hey user !!

Here's the answer you are looking for


8x³ - (2x - y)³

= 8x³ - [(2x)³ - y³ - 3(2x)(y)(2x - y)]

= 8x³ - [8x³ - y³ - 6xy(2x - y)]

= 8x³ - 8x³ + y³ + 6xy(2x - y)

= y³ + 12x²y - 6xy²



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