factorise the polynomial: 8x³-(2x-y)³
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Hi friend,
Here is your answer,
_____________________________________________________________
8x³-(2x-y)³
= 8x³ - [8x³ - y³ - 3*2x*y(2x-y)]
= 8x³ - [8x³ -y³ - 12x²y + 6xy²]
= 8x³ - 8x³ + y³ + 12x²y - 6xy²
= y³ + 12x²y - 6xy²
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
Here is your answer,
_____________________________________________________________
8x³-(2x-y)³
= 8x³ - [8x³ - y³ - 3*2x*y(2x-y)]
= 8x³ - [8x³ -y³ - 12x²y + 6xy²]
= 8x³ - 8x³ + y³ + 12x²y - 6xy²
= y³ + 12x²y - 6xy²
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
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