Factorise the Polynomial x^2-2+1/x^2-y^2
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Answer:
x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\\=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)
Step-by-step explanation:
Given ,\\x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}
=x^{2}+\frac{1}{x^{2}}+2\times x \times \frac{1}{x}-2x-\frac{2}{x}
=\big(x+\frac{1}{x}\big)^{2}-2\big(x+\frac{1}{x}\big)
=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)
Therefore,
x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\\=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)
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