factorise the polynomial
x^2-2x+5
Answers
Answered by
0
Step-by-step explanation:
x^2-2x+5
by squaring the root
x^2-2(1)x+(1)^2-(1)^2=-5
it's a identity a2+2ab+b2=(a+b)^2
that's why,
(x-1)^2=-5+(1)^2
(x-1)^2=-5+1
(x-1)^2=-4
x-1=√-4
we know that the value of under root (-4)is not defined.so, its roots are not possible
Answered by
0
Answer:
The given polynomial can't be factorized.
Step-by-step explanation:
x² - 2x + 5 = 0
Here, a = 1, b = -2, c = 5
So, D = b² - 4ac
= (-2)² - 4(1)(5)
= 4 - 20
= - 24
We know that when
- D ≥ 0, then the quadratic equation has real roots and
- when D < 0, then the quadratic equation has imaginary roots or we can say that its roots don't exist.
So, the given polynomial can't be factorized.
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