Question

Factorise the
polynomial :- x^2+3√3x+6​

Answer 1

${x}^{2} + 3 \sqrt{3} x + 6$

$= {x}^{2} + 2 \sqrt{3} x + \sqrt{3} x + 6$

$= x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} )$

$= (x + \sqrt{3} )(x + 2 \sqrt{3} )$

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Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-Factorise the

polynomial :- x^2+3√3x+6

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$⇛ {x}^{2} + 3 \sqrt{3} x + 6 = 0$

$⇛ {x}^{2} + 2 \sqrt{3} x + \sqrt{3}x + 6 = 0$

$⇛x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} )$

$⇛(x + \sqrt{3} )(x + 2 \sqrt{3} )$

$⇛x = - \sqrt{3} \: and \: x = - 2 \sqrt{3}$

HOPE IT HELPS YOU..

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