factorise the polynomial x cube minus 6 X square + 11 x minus 6
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Answered by
4
Answer:
x³-6x²+11x-6
if x=1
the polynomial becomes 0.
so, (x-1) is one factor
=>(x-1)(x²-5x+6)
=>(x-1)(x²-2x-3x+6)
=>(x-1)(x-2)(x-3)
Answered by
4
Factor the following:
x³- 6 x² + 11 x - 6
The possible rational roots of x^3 - 6 x^2 + 11 x - 6 are x = ± 1, x = ± 2, x = ± 3, x = ± 6. Of these, x = 1, x = 2 and x = 3 are roots. This gives x - 1, x - 2 and x - 3 as all factors:
Answer: |
| (x - 1) (x - 2) (x - 3)
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