Question

factorise the polynomials x ³+7x²-21x-27 using factor theorem.
Please answer it fastly.
I will mark you as brainliest.

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Answer 1

Answer:

hope it helps you

Step-by-step explanation:

Step-by-step explanation:x³+7x2-21x-27

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9=x-3xx-9-1x-9

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9=x-3xx-9-1x-9=x-3x-9x-1

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9=x-3xx-9-1x-9=x-3x-9x-1⇒x³+7x2-21x-27

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9=x-3xx-9-1x-9=x-3x-9x-1⇒x³+7x2-21x-27=x-3x-9x-1

Step-by-step explanation:x³+7x2-21x-27=x³-3x2+10x2-30x+9x-27=x²x-3-10xx-3+9x-3=x-3x2-10x+9=x-3x2-9x-x+9=x-3xx-9-1x-9=x-3x-9x-1⇒x³+7x2-21x-27=x-3x-9x-1 Hope this