factorise the problem x6-1
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Answer:
[1]:
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
[2]:
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
[3]:
a
3
+
b
3
=
(
a
+
b
)
(
a
2
−
a
b
+
b
2
)
x
6
−
1
=
(
x
3
)
2
−
1
2
=
(
x
3
−
1
)
(
x
3
+
1
)
by [1]
=
(
x
3
−
1
3
)
(
x
3
+
1
3
)
=
(
x
−
1
)
(
x
2
+
x
+
1
)
(
x
+
1
)
(
x
2
−
x
+
1
)
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