factorise the quadratic equation 2b²+10b+12=0
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Answer:
b= -3 and b= -2
Step-by-step explanation:
= 2b²+10b+12=0
Divide both sides by 2.
= b²+5b+6 = 0
= b²+3b+2b+6 = 0
= b×(b+3)+2b+6 = 0
= b×(b+3)+2(b+3) = 0
= (b+3) (b+2) = 0
= b+3 = 0 and b+2 = 0
= b = 0-3 and b = 0-2
= b= -3 and b = -2
•°• The values of b are -3 and -2.
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