Question

factorise the quadratic polynomials (3x+2y) ^2-6(3x2y) -72​

Answer 1

Answer:

$\left(3x+2y\right)^2-6\left(3x^2y\right)-72\\= \left(3x+2y\right)^2-6\cdot \:3x^2y-72\\= \left(3x+2y\right)^2-18x^2y-72\\=\left(3x\right)^2+2\cdot \:3x\cdot \:2y+\left(2y\right)^2-18x^2y-72\\=9x^2+12xy+4y^2-18x^2y-72$

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