Question

factorise the quadratic trinomials :
${x}^{2} + 13x + 40$
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Answer 1

$\huge\mathfrak\red{\star{\underline{\underline{Answer}}}}$

${x}^{2}+13x+40= 0$

${x}^{2}+8x+5x+40=0$

$x(x+8)+5(x+8) =0$

$(x+8)(x+5)=0$

$x=(-8),(-5)$

Hope it helps úh

Answer 2

Explanation:

its yur solution dear...