Question

Factorise the question (2 to 10) expressions

Answer 1

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Answer 2

$\huge\underline\mathfrak{Subject}$

Math

$\huge\underline\mathfrak{Topic}$

Factores

$\textbf{Solution}$

$\textbf{Step-By-Step-Solution}$

${x}^{2} - {y}^{2} - 2y - 1 = 0$

so it seem in eq that

$- ( {y}^{2} + 2y + 1 = 0 )$

$\textbf{Using,formula}$

${x}^{2} + {y}^{2} + 2xy = {(x + y)}^{2}$

so the above eq become

${x}^{2} - ( {y}^{2} + {1}^{2} + 2y) = 0$

${x }^{2} - {(y + 1)}^{2} = 0$

$\textbf{Using, formula}$

$({x}^{2} - {y}^{2} ) = (x - y)(x - y)$

so, above eq reduce in

$({x}- (y + 1)) \: \: \: \: ( {x}+ y + 1)$

$= x - y - 1$

or

${x} + y + 1$