Question

Factorise the question 4a^2+b^2-c^2+4ab​

Answer 1

Here's ur answer..

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Answer 2

4a² + b² - c² + 4ab

= (4a² + b² + 4ab) - c²

= {(2a)² + b² + 2(2a)(b)} - c²

We know that, x² + y² + 2xy = (x + y)²

Here x = 2a, y = b

By substituting the values :

= (2a + b)² - c²

Here let us consider (2a + b) = x, c = y

We know that x² - y² = (x + y)(x - y)

By substituting the values :

= (2a + b + c)(2a + b - c)

Hope it helps!!