Question

factorise the question

Answer 1

$\textbf{Solution}$

$<b>$a³+ b³ = (a+b)(a²-ab+b²)

$27 {a}^{3} + 64 {b}^{3} \\ \\ = ( {3a})^{3} + ( {4b})^{3} \\ \\ ( {3a})^{3} + ( {4b})^{3} \: IS \: IN \: THE \: FORM \: OF \: {a}^{3} + {b}^{3}$

=(3a)³+ (4b)³

=( 3a + 4b ){ (3a)² - (3a)(4b) + (4b)²}

=( 3a + 4b ) (9a² - 12 ab + 16b² )

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Answer 2

$\bold{\huge{\boxed{Hello.here.is.your.answer!!}}}$
${27 \: a}^{3} + {64 \: b}^{3} \\ {(3a)}^{3} + {(4b)}^{3} \: \: \: \: \: \: using( {a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )) \\ (3a + 4b)( {( 3a)}^{2} - (3a)(4b) + {(4b)}^{2} ) \\ \\ (3a + 4b)(9 {a }^{2} - 12ab +16 {b}^{2} )$
$\bold{\huge{\underline{\boxed{Hope.it.will. help.you!!}}}}$