Question

Factorise the question given in attachment

Answer 1

Answer:

$4x^{2} + 4xy + y^{2} - z^{2}$ = $(2x + y +z) (2x + y -z)$

Step-by-step explanation:

here, $4x^{2} + 4xy + y^{2} - z^{2}$

     = $[(2x)^{2} + 2 * 2x * y + y^{2}] - z^{2}$        [(a + b)² = a² + 2ab + b²]

     = $(2x + y)^{2} - z^{2}$

     = $(2x + y +z) (2x + y -z)$              [a² - b² = (a + b) (a-b)]

∴ $4x^{2} + 4xy + y^{2} - z^{2}$ = $(2x + y +z) (2x + y -z)$

hope it will help you.