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split 3x^3 as 2x^3 + x^3
so x^4 + 2x^3 + x^3 + 2x^2 -3x +3=0
x^3(x+2) + x^2(x+2) = -3(x+1)
(x^3+x^2) (x+2) =-3(x+1)
so one of the zeros must be (-1)
split 3x^3 as 2x^3 + x^3
so x^4 + 2x^3 + x^3 + 2x^2 -3x +3=0
x^3(x+2) + x^2(x+2) = -3(x+1)
(x^3+x^2) (x+2) =-3(x+1)
so one of the zeros must be (-1)
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