Question

factorise the suitable identities 4x²- 32xy + 64y²​

Answer 1

Used identity:-

$\boxed{\sf (a-b)^2=a^2-2ab+b^2}$

Solution:-

$\\ \sf\longmapsto 4x^2-32xy+64y^2$

• Break the terms and take them to thhe factored form

$\\ \sf\longmapsto (2x)^2-2(2x)(8y)+(8y)^2$

$\\ \sf\longmapsto (2x-8)^2$

• IT is your answer

Hope it helps

Answer 2

4x²- 32xy + 64y²

= (2x)² - 2(2x)(8y)+ (-8y)²

= (2x-8y)² [Using the following identity]

$x {}^{2} - 2xy + y {}^{2} = (x - y) {}^{2}$