Question

Factorise the sum.
please give me solution.​

Answer 1

$( {2p - 4q})^{2} - ({3p + 2q})^{2} \\ \\ 4 {p}^{2} + 16 {q}^{2} - 2(2p)(4q) - 9 {p}^{2} - 4 {q}^{2} - 2(3p)(2q) \\ \\ - 5 {p}^{2} + 12 {q}^{2} - 16pq - 12pq \\ \\ - 5 {p}^{2} + 12 {q}^{2} - 28pq \\ \\ 5 {p}^{2} - 12 {q}^{2} + 28pq$

Answer 2

HEY MATE HERE IS YOUR ANSWER--

▂ ▃ ▄ ▅ ▆ █ SG█ ▆ ▅ ▄ ▃ ▂

${(2p - 3q)}^{2} - {(3p + 2q)}^{2} \\ \\ {4p}^{2} + {9q}^{2} - {12pq}^{2} - ( { 9p}^{2} + {4q}^{2} + {12pq}^{2}) \\ \\ {4p}^{2} + {9q}^{2} - {12pq}^{2} - {9p}^{2} - {4q}^{2} - {12pq}^{2} \\ \\ - {5p}^{2} + {5q}^{2} - {24pq}^{2} \\ \\ {5p}^{2} - {5q}^{2} + {24pq}^{2}$

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