Question

Factorise the team:
(2x+5y)² -1​

Answer 1

Answer:

${\sf{\green{\underline{\overline{Answer:-}}}}}$

☘ғᴀᴄᴛᴏʀɪsᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇxᴘʀᴇssɪᴏɴ ɪs (2x+5ʏ+1)(2x+5ʏ-1).

${\sf{\purple{\underline{\overline{Given:-}}}}}$

Given:−

☘ᴘ(x) = (2x+5ʏ)² -1

${\sf{\orange{\underline{\overline{To \: find:-}}}}}$

☘ғᴀᴄᴛᴏʀɪsᴇ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇxᴘʀᴇssɪᴏɴ.

${\sf{\pink{\underline{\overline{Solution:-}}}}}$

= (2x+5ʏ)² -1

= (2x+5ʏ)² -(1)²

= (2x+5ʏ+1)(2x+5ʏ-1)

☘ғᴀᴄᴛᴏʀɪsᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇxᴘʀᴇssɪᴏɴ ɪs (2x+5ʏ+1)(2x+5ʏ-1).

______________________

${\sf{\red{\underline{\overline{Important \: formulae:-}}}}}$

(ᴀ+ʙ)² = ᴀ²+ʙ²+2ᴀʙ

(ᴀ-ʙ)² = ᴀ²+ʙ²-2ᴀʙ

(ᴀ+ʙ)(ᴀ-ʙ) = ᴀ²-ʙ²

(ᴀ+ʙ)³ = ᴀ³+ʙ³+3ᴀʙ(ᴀ+ʙ)

(ᴀ-ʙ)³ = ᴀ³-ʙ³-3ᴀʙ(ᴀ-ʙ)

ᴀ³+ʙ³ = (ᴀ+ʙ)(ᴀ²+ʙ²-ᴀʙ)

ᴀ³-ʙ³ = (ᴀ-ʙ)(ᴀ²+ʙ²+ᴀʙ)

(ᴀ+ʙ)² = (ᴀ-ʙ)²+4ᴀʙ

(ᴀ-ʙ)² = (ᴀ+ʙ)²-4ᴀʙ

Answer 2

$\huge{ \green} \fcolorbox{tomato}{b}{ \underline{ \color{red}{ꪖꪀᦓ᭙ꫀ᥅}}}$

___________________________________

$\bold \pink{given}$

❤ᴘ(x) = (2x+5ʏ)² -1

$\bold \red{to \: find}$

❤ғᴀᴄᴛᴏʀɪsᴇ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇxᴘʀᴇssɪᴏɴ.

$\sf \underline \pink{solution}$

= (2x+5ʏ)² -1

= (2x+5ʏ)² -(1)²

= (2x+5ʏ+1)(2x+5ʏ-1)

ғᴀᴄᴛᴏʀɪsᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇxᴘʀᴇssɪᴏɴ ɪs (2x+5ʏ+1)(2x+5ʏ-1).❤~