factorise the term , 6ab+12bc
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Answered by
1
Answer:
6ab + 12bc = 0. => 6b (a + 2c) = 0. case 1. (a + 2c) = 0. => a = (-2c)
Answered by
3
Answer:
6b(a+2c)
STEP BY STEP
take 6b common
then in first term a left,in second term 2c left as it is under sum we'll get 6b(a+2c)
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