Question

factorise the term using middle term splitting only

Answer 1

Mark as Brainelist,please
The question is wrong i have correct it 3 should be 5 ok friend${x}^{2} - 2 \sqrt{5}x + 5 \\ = {x}^{2} - ( \sqrt{5} + \sqrt{5}) + 5 \\ = {x}^{2} - \sqrt{5} x - \sqrt{5} x + 5 \\ = x(x - \sqrt{5} ) - \sqrt{5} (x - \sqrt{5} ) \\ = (x - \sqrt{5} )(x - \sqrt{5} ) \\ = ({x - \sqrt{5} })^{2}$

Answer 2

Answer:

(x -√5 - √2)(x- √5 + √2)

Step-by-step explanation:

Given that

x² -2√5 x + 3

We can write

2√5 x = (√5 + √2)x + (√5 - √2)x

3 =  (√5 + √2) (√5 - √2)

So,

x² -(√5 + √2)x - (√5 - √2)x + (√5 + √2) (√5 - √2)

taking commons

x (x - (√5 + √2)) -(√5 - √2)(x - (√5 + √2))

taking commons again

(x - (√5 + √2))(x- (√5 - √2))

In simplified form

(x -√5 - √2)(x- √5 + √2)