Question

factorise the term:
x^2-✓3 x-6​

Answer 1

Step-by-step explanation:

x^2 -2√3x + √3x - 6

= x(x - 2√3) + √3(x-2√3)

= (x-2√3)(x+√3)

Answer 2

HERE IS YOUR ANSWER MATE......;

SEE ATTACHMENT FOR ANSWER ✔️✔️

• Extra Information :-

• I attached 2 images.... Confirmed that u seen both attachment.

• When b2−4ac=0 there is one real root.

• When b2−4ac>0 there are two real roots.

• When b2−4ac<0 there are two complex roots.

• Quadratic Formula:

$= > x = \frac{ - b + \sqrt{ b {}^{2} - 4ac} }{2a}$

Note - Only applicable for where a ≠ 0 and equation in the form

$ax {}^{2} + bx + c</em><em> </em><em>=</em><em> </em><em>0</em><em>$

HOPE IT'S HELPFUL....:-)