factorise the the following using identities.
a. p^4+2p^2q^2+q^4
b. 36z^2-49x^2
c. 196p^2-121q^2
Answers
Answered by
1
A. p^4+2p^2q^2+q^4
=(p^2)^2+2×p^2×q^2+(q^2)^2
=(p^2+q^2)^2
=(p^2+q^2) (p^2+q^2)
B. 36z^2-49x^2
=(6z)^2-(7x)^2
=(6z+7x) (6z-7x)
C. 196p^2-121q^2
=(14p)^2-(11q)^2
=(14p+11q) (14p-11q)
=(p^2)^2+2×p^2×q^2+(q^2)^2
=(p^2+q^2)^2
=(p^2+q^2) (p^2+q^2)
B. 36z^2-49x^2
=(6z)^2-(7x)^2
=(6z+7x) (6z-7x)
C. 196p^2-121q^2
=(14p)^2-(11q)^2
=(14p+11q) (14p-11q)
Answered by
0
i am solving c
(14p)^2 - (11q)^2
(14p+11q) (14p-11q)
this is b one
answer
(6z+7x)(6z-7x)
(14p)^2 - (11q)^2
(14p+11q) (14p-11q)
this is b one
answer
(6z+7x)(6z-7x)
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