Question

Factorise the trinomial x²+7x+12​

Answer 1

$\sf \large \bold{Given\: expression} \\ \\ \sf \: {x}^{2} + 7x + 12 \: = \: 0 \\ \\ \color{lime} \sf \: Splitting\:the \: middle \: term \\ \\ \sf {x}^{2} + 5x - 2x + 12 \: = \: 0 \\ \\ \color{red} \: \sf \:Taking \: common \: term \: out \: \\ \\ \sf \: x \: (x + 5) \: - \: 2 \: (x + 12) \: = \: 0 \: \\ \\ \sf \: (x - 2 )\: (x + 5) \: (x + 12) \: = \: 0 \\ \\ \sf \: x \: - \: 2 = 0 \: \: | \: \: x \: + 5 \: = 0 \: \: | \: \: x \: + \: 12 = 0 \\ \\ \sf \: x \: = \: 2 \: \: | \: \: x = - 5 \: \: | \: \: x = - 12$

Answer 2

Answer:

Factorisation problem