Factorise the y3-3y2 +2y-6-xy+3x
Answers
Answer:
Step-by-step explanation:
y3-3y2+2y-6-xy+3x
Final result :
(y - 3) • (y2 - x + 2)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "y2" was replaced by "y^2". 1 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((((y3)-3y2)+2y)-6)-yx)+3x
Step 2 :
Trying to factor by pulling out :
2.1 Factoring: y3-3y2-yx+2y+3x-6
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -yx+2y
Group 2: y3-3y2
Group 3: 3x-6
Pull out from each group separately :
Group 1: (x-2) • (-y)
Group 2: (y-3) • (y2)
Group 3: (x-2) • (3)
Looking for common sub-expressions :
Group 1: (x-2) • (-y)
Group 3: (x-2) • (3)
Group 2: (y-3) • (y2)
Adding (1) + (3): (x-2) • (-y+3) Then adding (2): y2 • (y-3) -------------------
We end up with :
(-y2+x-2) • (3-y)
Which is the desired factorization
Trying to factor a multi variable polynomial :
2.2 Factoring -1 • (y2 - x + 2)
Final result :
(y - 3) • (y2 - x + 2)