factorise then divide: 156y3(36y2-64)/104y2(6y+8)
Answers
Answer:
(12)(3y)( 6y − 8 )
Step-by-step explanation:
We have : 156 y3 ( 36y2 − 64 )104 y2 ( 6y + 8 )156 y3 36y2 - 64 104 y2 6y + 8 , So we write it , As :
⇒3y ( 36y2 − 64 )2 ( 6y + 8 )
⇒3y ( (6y)2 − 64 )2 ( 6y + 8 )
⇒3y ( ( 6y + 8 ) ( 6y − 8 ) )2 ( 6y + 8 ) ( As we know ( a2 − b2 ) = ( a − b ) ( a + b ) )
⇒3y ( 6y + 8 ) ( 6y − 8 ) 2 ( 6y + 8 )
⇒3y ( 6y − 8 ) 2
⇒(3y 2)( 6y − 8 )
⇒(12)(3y)( 6y − 8 )
Answer:
((156•(y3))•——————————————)•y2)•(6y+8) 104
STEP2:
36y2 - 64 Simplify ————————— 104
STEP3:Pulling out like terms
3.1 Pull out like factors :
36y2 - 64 = 4 • (9y2 - 16)
Trying to factor as a Difference of Squares:
3.2 Factoring: 9y2 - 16
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 9 is the square of 3
Check : 16 is the square of 4
Check : y2 is the square of y1
Factorization is : (3y + 4) • (3y - 4)
Equation at the end of step3:
(3y+4)•(3y-4) (((156•(y3))•—————————————)•y2)•(6y+8) 26
STEP 4 :
Equation at the end of step4:
(3y + 4) • (3y - 4) (((22•3•13y3) • ———————————————————) • y2) • (6y + 8) 26
STEP5:
Dividing exponents:
5.1 22 divided by 21 = 2(2 - 1) = 21 = 2
Canceling Out:
5.2 Canceling out 13 as it appears on both sides of the fraction line
Equation at the end of step5:
(6y3 • (3y + 4) • (3y - 4) • y2) • (6y + 8)
STEP6:
Multiplying exponential expressions :
6.1 y3 multiplied by y2 = y(3 + 2) = y5
Equation at the end of step6:
(2•3y5) • (3y + 4) • (3y - 4) • (6y + 8)
STEP7:
STEP8:Pulling out like terms
8.1 Pull out like factors :
6y + 8 = 2 • (3y + 4)
Multiplying exponents:
8.2 21 multiplied by 21 = 2(1 + 1) = 22
Multiplying Exponential Expressions:
8.3 Multiply (3y + 4) by (3y + 4)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (3y+4) and the exponents are :
1 , as (3y+4) is the same number as (3y+4)1
and 1 , as (3y+4) is the same number as (3y+4)1
The product is therefore, (3y+4)(1+1) = (3y+4)2
Final result :
(22•3y5) • (3y + 4)2 • (3y - 4)
Step-by-step explanation:
pls like and have nice day