Question

factorise these questions​

Answer 1

Answer:

$\\\tt (x-\dfrac{1}{x}) (x - \dfrac{1}{x}-3 )$

Step-by-step explanation:

$\\\tt x^2 + \dfrac{1}{x^2} -2 - 3x + \dfrac{3}{x} \\\tt x^2 + \dfrac{1}{x^2} -2(x)(\dfrac{1}{x}) - 3x + \dfrac{3}{x} \\\tt (x-\dfrac{1}{x})^2 -3(x - \dfrac{1}{x}) \\\tt (x-\dfrac{1}{x}) (x - \dfrac{1}{x}-3 )$