Question

Factorise these

x²-5x-36

Answer 1

Answer:x = 9 and x = -4

Step-by-step explanation:

x²-5x-36=0

x²+4x-9x-36=0

x(x+4)-9(x+4)=0

(x-9)(x+4)=0

x=9 and x=-4

Answer 2

Answer:

$\red { Factors \:of \: x^{2} -5x-36}$

$\green {= (x-9)(x+4)}$

Step-by-step explanation:

$Given \: quadratic \: expression : x^{2} -5x-36$

/* Splitting the middle term, we get

$= x^{2} - 9x + 4x -36 \\= x( x - 9 ) + 4( x - 9 )\\= (x-9)(x+4)$

Therefore.,

$\red { Factors \:of \: x^{2} -5x-36}$

$\green {= (x-9)(x+4)}$

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