Question

factorise this ....​

Answer 1

Answer:(x-1/x)^2-3(x-1/x)

x-1/x[(x-1/x)-3]

Step-by-step explanation:

Answer 2

${x}^{2} + \frac{1}{ {x}^{2} } - 2 - 3x + \frac{3}{x}$

$= ({x}^{2} + \frac{1}{ {x}^{2} } - 2.x. \frac{1}{x} ) - 3(x - \frac{1}{x} )$

$= {(x - \frac{1}{x} )}^{2} - 3(x - \frac{1}{x} )$

• Now take (x - $\frac{1}{x}$) as commom factor from both terms.

$= {(x - \frac{1}{x}) }(x - \frac{1}{x} - 3)$