Question

factorise this 6x^2-12x+6 by splitting middle term i will mark you as brainliest if you answer this

Answer 1

Answer:

$\bigstar{\bold{Zeros\:of\:polynomial\:are\:1\:and\:1}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• p(x) = 6x²-12x+6

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• The zeros of the polynomial

$\Large{\underline{\underline{\bf{Solution:}}}}$

↦ 6x²-12x+6 = 0

↦ By splitting term middle term, we get

    6x²-6x-6x+6=0

↦ Taking the common factors out

    6x(x-1)-6(x-1)

    (x-1)(6x-6) = 0

↦ Either x-1=0

   x=1

↦ Or 6x-6=0

    x=1

$\boxed{\bold{Zeros\:of\:polynomial\:are\:1\:and\:1}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

↦ The zeros of a polynomial can be found out by 3 methods

• Factorization method
• Splitting the middle term
• Completing the square method