Question

Factorise this equation​

Answer 1

$27p {}^{3} - \frac{1}{216} - \frac{9}{2} p {}^{2} + \frac{1}{4} p \\ =( 3p) {}^{3} - 3(3p) {}^{2} ( \frac{1}{6} ) +3(3p)( \frac{1}{6} ) {}^{2} - (\frac{1}{6} ) {}^{3} \\ =( 3p - \frac{1}{6} ) {}^{3} \\ = (3p - \frac{1}{6} )(3p - \frac{1}{6} )(3p - \frac{1}{6} )$

Answer 2

Answer:

(3p-(1/6))^3

Step-by-step explanation:

answer is in the above picture