Factorise this equation.
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Heya !!
8a³ + √27b³
=> (2a)³ + (√3b)³
as we know, a³+b³= (a+b)(a²-2ab+b²)
So, (2a+√3b)(4a²-4√3ab+3b²)
The factors are (2a+√3b) and (4a²-4√3ab+3b²)
8a³ + √27b³
=> (2a)³ + (√3b)³
as we know, a³+b³= (a+b)(a²-2ab+b²)
So, (2a+√3b)(4a²-4√3ab+3b²)
The factors are (2a+√3b) and (4a²-4√3ab+3b²)
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