factorise this one please
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Q. Factorisation »
6. (5a - 3b)² - 16b²
= (5a - 3b)² - (4b)²
= [ (5a - 3b) + (4b) ] [ (5a - 3b) - (4b) ]
= ( 5a - 3b + 4b ) ( 5a - 3b - 4b )
= ( 5a + b ) ( 5a - 7b )
Answer » (5a + b) (5a - 7b)
Identities Used »
a² - b² = (a + b) (a - b)
where,
a² = (5a - 3b)²
b² = (4b)²
Note » (4b)² = 4² × b² = 16b²
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6. (5a - 3b)² - 16b²
= (5a - 3b)² - (4b)²
= [ (5a - 3b) + (4b) ] [ (5a - 3b) - (4b) ]
= ( 5a - 3b + 4b ) ( 5a - 3b - 4b )
= ( 5a + b ) ( 5a - 7b )
Answer » (5a + b) (5a - 7b)
Identities Used »
a² - b² = (a + b) (a - b)
where,
a² = (5a - 3b)²
b² = (4b)²
Note » (4b)² = 4² × b² = 16b²
✪ Be Brainly ✪
Answered by
1
(5a-3b)²-16b²
= (5a - 3b) - (4b)²
= [(5a-3b)+4b][(5a-3b)-4b]
= (5a+b)(5a-7b)
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