Math, asked by hitanshi21, 8 months ago

FACTORISE this please answer with explaination ​

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Answered by mysticd
1

2x^{2}+y^{2}+8z^{2}-2\sqrt{2}xy+4\sqrt{2}yz-8xz

 = (-\sqrt{2}x)^{2} + y^{2}+(2\sqrt{2}z)^{2} +2\times(-\sqrt{2}x)\times y + 2\times y\times(2\sqrt{2}y) + 2\times (2\sqrt{2}y)\times(-\sqrt{2}x)

 = ( -\sqrt{2}x + y + 2\sqrt{2}z )^{2}

 = ( -\sqrt{2}x + y + 2\sqrt{2}z )( -\sqrt{2}x + y + 2\sqrt{2}z )

Therefore.,

 \red {2x^{2}+y^{2}+8z^{2}-2\sqrt{2}xy+4\sqrt{2}yz-8xz }

 \green {= ( -\sqrt{2}x + y + 2\sqrt{2}z )( -\sqrt{2}x + y + 2\sqrt{2}z )}

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