Question

factorise this plsss fast

Answer 1

m^8-11m^4n^4-80n^8
=m^8-16m^4n^4+5m^4n^4-80n^8
=(m^4n^4+5) (m^4n^4-16)
=(m^4n^4+5)(m^2n^2+4)
(mn+2)(mn-2)

Answer 2

✪ Formula and Concept used :-

1. Splitting method

2. a² - b² = ( a + b )( a - b )

$\Longrightarrow{\boxed{\bold{Answer:( {m}^{4} + 5 {n}^{4} )( {m}^{2} + 4 {n}^{2} )(m + 2n)(m - 2n) }}}$

$\textbf{\underline{Step-by-step explanation :- }}$

$= {m}^{8} - 11 {m}^{4} {n}^{4} - 80 {n}^{8} \\ \\ = {m}^{8} - 16 {m}^{4} {n}^{4} + 5 {m}^{4} {n}^{4} - 80 {n}^{8} \\ \\ = {m}^{4} ( {m}^{4} - 16 {n}^{4} ) + 5 {n}^{4} ( {m}^{4} - 16 {n}^{4} ) \\ \\ = ( {m}^{4} + 5 {n}^{4} ) ( {m}^{4} - 16 {n}^{4} ) \\ \\ = ( {m}^{4} + 5 {n}^{4} )( { ({m}^{2}) }^{2} - { {(4n}^{2}) }^{2} ) \\ \\ = ( {m}^{4} + 5 {n}^{4} )( {m}^{2} + 4 {n}^{2} )( {m}^{2} - 4 {n}^{2} ) \\ \\ = ( {m}^{4} + 5 {n}^{4} )( {m}^{2} + 4 {n}^{2} )( {m}^{2} - {(2n)}^{2} ) \\ \\ = ( {m}^{4} + 5 {n}^{4} )( {m}^{2} + 4 {n}^{2} )(m + 2n)(m - 2n)$