factorise this question
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4(m+n)^2-28p (m+n)+49p^2
Let m+n= q
=4q^2-28pq+49p^2
=(2q)^2-2 (2q)(7p)+(7p)^2
=(2q-7p)^2
=[2 (m+n)-7p^2]
Let m+n= q
=4q^2-28pq+49p^2
=(2q)^2-2 (2q)(7p)+(7p)^2
=(2q-7p)^2
=[2 (m+n)-7p^2]
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